**NCERT solutions for class 10 Maths**

**Chapter 7**

**Coordinate Geometry**

**Exercise 7.3**

**Ex 7.3 Question 1.**

**Find the area of the triangle whose vertices are:**

**(i) (2, 3), (-1, 0), (2, -4)**

**(ii) (-5, -1), (3, -5), (5, 2)**

**Solution:**

**Ex 7.3 Question 2.**

** In each of the following find the value of ‘k’, for which the points are collinear.**

**(i) (7, -2), (5, 1), (3, -k)**

**(ii) (8, 1), (k, -4), (2, -5)**

**Solution:**

**Ex 7.3 Question 3.**

** Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area to the area of the given triangle.**

**Solution:**

**Ex 7.3 Question 4.**

** Find the area of the quadrilateral whose vertices, taken in order, are**

**(-4, -2), (-3, -5), (3, -2) and (2, 3).**

**Solution:**

**Ex 7.3 Question 5.**

** You have studied in Class IX that a median of a triangle divides it into two triangles of equal areas. Verify this result for ΔABC whose vertices are A (4, – 6), B (3, – 2) and C (5, 2).**

**Solution:**